6x^2-25x+19=0

Solution for 6x^2-25x+19=0 equation:

6x^2-25x+19=0

a = 6; b = -25; c = +19;
Δ = b2-4ac
Δ = -252-4·6·19
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-13}{2*6}=\frac{12}{12}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+13}{2*6}=\frac{38}{12}
=3+1/6
$